(2x+3)^(2)+7(2x+3)+10=0

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Solution for (2x+3)^(2)+7(2x+3)+10=0 equation: 



(2x+3)^(2)+7(2x+3)+10=0

We multiply parentheses

(2x+3)^2+14x+21+10=0

We add all the numbers together, and all the variables

14x+(2x+3)^2+31=0

We move all terms containing x to the left, all other terms to the right

14x+(2x+3)^2=-31

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